Предмет: Химия, автор: dididi14

задача по химии пожалуйста

Приложения:

Ответы

Автор ответа: Platinum15

Дано:
m(CaCO3) = 200 г
w(примесей) = 20 %
Найти:
V(CO2) -?

Решение:
CaCO3 +2HCl = CaCl2 +CO2 +H2O
m(CaCO3) = 200 - 200*0.2 = 160 г
M(CaCO3) = 100 г\моль
n(CaCO3) = 160/100 = 1.6 моль
n(CO2) = n(CaCO3) = 1.6 моль
V(CO2) = 1.6 *22.4 = 35.84 л

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