Question

$4 {x}^{2} - 3x = 4$

Answer 1

4x^2-3x-4=0
D=b^2-4*a*c
D=(-3)^2-4*4*(-4)=9+64=√73
x1=(-(-3)+√73)/2*4 =1.443
x2=(-(-3)-√73)/2*4=-0.693