Question

Решите систему уравнений
2х/3+4y/5=0

3x/2+y=-4

Answer 1

$\left \{ {{ \frac{2x}{3}+ \frac{4y}{5} =0} \atop { \frac{3x}{2} +y=-4}} \right. \\ \\ \left \{ {{10x+12y=0} \atop {3x+2y=-8}} \right. \\ \\ \left \{ {{10x+12y=0} \atop {-18x-12y=48}} \right. \\ \\ -8x=48 \\ \\ x=-6 \\ \\ -60+12y=0 \\ \\ 12y=60 \\ \\ y=5 \\ \\ OTVET: (-6;5)$