Question

интеграл от 3 до 1 (x^2-2x)dx

Answer 1

$\int\limits^3_1 {(x^2-2x)} \, dx=(\frac{x^3}{3}-2\cdot \frac{x^2}{2})\Big |_1^3=\frac{27}{3}-9-(\frac{1}{3}-1)=\\\\=1-\frac{1}{3}=\frac{2}{3}$