Предмет: Математика, автор: Котейка1258136

В 500 г 20% раствора серной кислоты добавили 300 г воды. Какова концентрация полученного растрвора

Ответы

Автор ответа: Kolya07

300г ÷ 20= 15(%) в 300г
15%+20%=35 (%)
Ответ:35% концентрация раствора.

Автор ответа: Malika72817951

500:20=15 300+15=315 (Как то так?)

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