Question

sin(x+1)cos2(x+1)=sin3(x+1)cos4(x+1)

Answer 1

1/2*(sin(x+1-2x-2)+sin(x+1+2x+2))=
1/2*(sin(3x+3-4x-4)+sin(3x+3+4x+4))

Sin(-x-1)+sin(3x+3)=sin(-x-1)+sin(7x+7)
Sin(3x+3)-sin(7x+7)=0
2*cos(5x+5)*sin(-2x-2)=0
Cos(5x+5)=0 или sin(2x+2)=0
Первое
5х+5=п/2+пn
5x=п/2-5+пn
X=п/10-1+пn/5,n€ Z
Второе
2х+2=пn
2X=пn-2
X=пn/2-1, n€Z