Question

ПОМОГИТЕЕЕЕ С АЛГЕБРОЙ ПОЖАЛУЙСТАААА ПРОШУУУУУУУУУУУУУ

Answer 1

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Answer 2

Сразу разложу и сведу:

$\frac{8 x^{2} y^{2}}{(x-y)(x+y)}: \frac{x(x+y)-x(x-y)}{(x+y)(x-y)}= \\ \\ = \frac{8 x^{2} y^{2}}{(x-y)(x+y)}: \frac{x^{2}+xy-x^{2}+xy}{(x-y)(x+y)}=\frac{8 x^{2} y^{2}}{(x-y)(x+y)}: \frac{2xy}{(x-y)(x+y)}= \\ \\ =\frac{8 x^{2} y^{2}}{(x-y)(x+y)}* \frac{(x-y)(x+y)}{2xy} =4xy$