Question

решите уравнение 2-(4-x)^2=x(3-x)

Answer 1

$2 - (4 - x) {}^{2} = x(3 - x) \\ 2 - (16 - 8x + x {}^{2}) = 3x - x {}^{2} \\ 2 - 16 + 8x - x {}^{2} = 3x - x {}^{2} \\ 2 - 16 + 8x = 3x \\ 8x - 3x = 14 \\ 5x = 14 \\ x = \frac{14}{5} \\ x = 2.8$

Answer 2

2-(4-x)^2=x(3-x)
2-(16-8x+x^2)=3x-x^2
2-16+8x-x^2=3x-x^2
2-16+8x=3x
-14+8x=3x
8x-3x-=14
5x=14
x=14:5=2,8