Question

Помогите пожалуйста!

Answer 1

$x_{n} = \frac{ \sqrt{n}-1 }{2n} \\ \\ x_{1} = \frac{ \sqrt{1}-1 }{2*1} =0 \\ \\ x_{2} = \frac{ \sqrt{2}-1 }{4} \\ \\ x_{3} = \frac{ \sqrt{3}-1 }{6} \\ \\ x_{4} = \frac{ \sqrt{4}-1 }{2*4} = \frac{1}{8}$