Question

Вычислите :
Sin315°×cos(-210°)×tg300°×ctg(-240)

Answer 1

$Sin315 ^{o} *Cos(-210) ^{o}*tg300 ^{o} *Ctg(-240) ^{o}=-Sin(360 ^{o}-45 ^{o} )*$$Cos(180 ^{o} +30 ^{o} )*tg(360 ^{o}-60 ^{o})*Ctg( 180 ^{o} +60 ^{o} ) =-(-Sin45 ^{o})*($-$Cos30 ^{o})*(-tg60 ^{o})* (Ctg60 ^{o} )= \frac{ \sqrt{2} }{2} * \frac{ \sqrt{3} }{2} = \frac{ \sqrt{6} }{4}$