Question

15 балов,умоляю быстрее

Answer 1

1) sinα=+-√(1-cos²α)=+-√(1-⅓²)=+-√(9/9 - 1/9)=
+-√(8/9)=+-⅔ √2.

tgα=sinα/cosα= (+-⅔ √2)/(⅓)=+-2√2.
ctgα=1/tgα=1/(+-2√2)=+-1/(2√2).

2) ctgα=1/tgα=¼.