Question

Решите неравенство
log₅ (3x+2) < 2

Answer 1

log₅ (3x+2) < 2
$ODZ:x\ \textgreater \ -2/3 \\ \\ log_{5} (3x+2)\ \textless \ log_{5} 25 \\ \\ 5\ \textgreater \ 1 \\ \\ 3x+2\ \textless \ 25 \\ \\ 3x\ \textless \ 23 \\ \\ x\ \textless \ 23/3 \\ \\ otvet: - \frac{2}{3} \ \textless \ x\ \textless \ 7 \frac{2}{3}$