Question

Решите пример ( 4 целых 5/12 + 1 целая 3/4) : (6 целых 2/15 -1 целая 1/5)

Answer 1

$(4 \frac{5}{12} + 1 \frac{3}{4} ) \div (6 \frac{2}{15} - 1 \frac{1}{5} ) = (4 \frac{5}{12} + 1 \frac{9}{12} ) \div (6 \frac{2}{15} - 1 \frac{3}{15} ) = \\ = 5 \frac{14}{12} \div (5 \frac{17}{15} - 1 \frac{3}{15} ) = 5 \frac{7}{6} \div 4 \frac{14}{15} = \frac{37}{6} \times \frac{15}{74} = \frac{15}{6 \times 2} = \frac{15}{12} = \\ = 1 \frac{3}{12} = 1 \frac{1}{4} = 1.25$