Question

0,2(1,3−1/7x+0(0,3x−11,5(10x−0,2)))−0,4x=0

Answer 1

1/5×(1,3-1/7x+0)-0,4x=0
1/5×(13/10-1/7x)-0,4x=0
13/50-1/35x-0,4x=0
13/50-1/35x-2/5x=0
13/50-3/7x=0
91-150x=0
-150x=-91
x=91/50