Question

11 класс срочно
Помогите
Номер 352 (2)
Ответ(- бескон;0)(60;+бескон)

Answer 1

$(x-7)*12+ \frac{(x-6) ^{2} }{3}*12\ \textgreater \ \frac{(x+4) ^{2} }{2}*12- \frac{(x+2)(x+6)}{4} *12\\\\12x- 84+4( x^{2} -12x+36)\ \textgreater \ 6( x^{2} +8x+16)-3( x^{2} +8x+12)\\\\12x-84+4 x^{2} -48x+144 \ \textgreater \ 6 x^{2} +48x+96-3 x^{2} -24x-36\\\\4 x^{2} -36x+60\ \textgreater \ 3 x^{2} +24x+60\\\\ x^{2} -60x\ \textgreater \ 0\\\\x(x - 60)\ \textgreater \ 0$
          +                     -                          +
___________₀___________₀___________
                     0                     60
x ∈ (- ∞ ; 0) ∪ (60 ; + ∞)