Question

-24ab-(4a-3b)² при a=√5 b=√2

Answer 1

-24аb-(4a-3b)²=-24ab-(16a²-24ab+9b²)=-24ab-16a²+24ab-9b²=-16a²-9b²
если
$a = \sqrt{5} \: \: \: b = \sqrt{2}$
,то
$- 16 \times { \sqrt{5} }^{2} - 9 \times { \sqrt{2} }^{2} = - 16 \times 5 - 9 \times 2 = - 80 - 18 = - 98$