Предмет: Химия, автор: Olenka08

3. Рассчитайте массу оксида алюминия и количество воды, которые образовались при разложении гидроксида алюминия массой 156 г.

Ответы

Автор ответа: nmatsiuk
2
2Al(OH)3=Al2O3+3H2O n(Al(OH)3)=156:78=2 моль. n(Al2O3)= 1 моль. m(Al2O3)= 1×102=102 г. m(H2O)=156-102=54 г
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