Question

11/169+17/91=?
73/140+125/196=?

Answer 1

$\frac{11}{169} + \frac{17}{91} = \frac{11}{13*13} + \frac{17}{13*7} = \frac{11*7+17*13}{13*13*7}= \frac{77+221}{169*7}=\frac{298}{1183}$

$\frac{73}{140} + \frac{125}{196} = \frac{73}{14*10} + \frac{125}{14*14} = \frac{73*14+125*10}{14*14*10} =\frac{1022+1250}{196*10} =\frac{2272}{1960} = \frac{284}{245}$