Question

а)b^2-6ab+9a^2+12a-4b. b)x^2+y^2+2xy+2x+2y+1

Answer 1

$a)b^2-6ab+9a^2+12a-4b=$
$=(b-3a)^2+4(3a-b)=$
$=(b-3a)^2-4(b-3a)=$
$=(b-3a)(b-3a-4).$

$b)x^2+y^2+2xy+2x+2y+1 =$
$= (x+y)^2+2(x+y)+1=$
$=(x+y)(x+y+2)+1.$