Question

d^2+0,2d+0,01−4d^2=0

Answer 1

d² + 0.2d + 0.01-4d² = 0
-3d² + 0.2d + 0.01 = 0
-300d² + 20d + 1 = 0
300d² - 20d - 1 = 0
D = b² - 4ac = (-20)² - 4·300·(-1) = 1600
Дроби: https://i.paste.pics/2qe9d.png