Question

памагити алгебра ето злоо

Answer 1

$\mathtt{\frac{x^3+8}{6x^2+11x-2}=\frac{(x+2)(x^2-2x+4)}{(6x-1)(x+2)}=\frac{x^2-2x+4}{6x-1}}$

$\mathtt{\frac{x^2-4}{5x-x^2-6}=\frac{4-x^2}{x^2-5x+6}=\frac{(2-x)(2+x)}{(x-2)(x-3)}=\frac{2+x}{3-x}}$

$\mathtt{\frac{x^2+2x-15}{4x-x^2-3}=\frac{(x+5)(3-x)}{(x-1)(x-3)}=\frac{x+5}{1-x}}$