Question

y=sin^2x/cosx найти производную

Answer 1

$y= \frac{sin^{2}x}{cosx}$
$y=sinx*tgx$
$y'=(sinx)'*tgx+(tgx)'*sinx$$y'=cosx*tgx+ \frac{sinx}{cos^{2}x }$$y'=sinx(1+ \frac{1}{cos^ {2}})$