Question

сравнить √24+√26 с √22+√28

Answer 1

$\displaystyle\sqrt{24}+ \sqrt{26}? \sqrt{22}+ \sqrt{28}\\\\( \sqrt{24}+ \sqrt{26})^2?(\sqrt{22}+ \sqrt{28})^2\\\\24+2 \sqrt{24*26}+26?22+2 \sqrt{22*28}+28\\\\50+2 \sqrt{624}?50+2 \sqrt{616}\\\\ \sqrt{624}\ \textgreater \ \sqrt{616}$

значит 
$\displaystyle\sqrt{24}+ \sqrt{26}\ \textgreater \ \sqrt{22}+ \sqrt{28}$