Предмет: Математика, автор: chymychkinanastya

(5a^3-4b)^2+(4b+5a^3)^2 пооомооогитее срочно (^ степень)

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Автор ответа: Alena3005

2

(5a^3-4b)^2+(4b+5a^3)^2=25а^6-40a^3b+16b^2+16b^2+40a^3b+25a^6=50a^6+32b^2

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