Question

Интеграл (1+ctg^2+10x) * dx

Answer 1

$\int (\underbrace {1+ctg^2x}_{1/sin^2x}+10x)dx=\int (\frac{1}{sin^2x}+10x)dx=\\\\=-ctgx+10\cdot \frac{x^2}{2}+C=-ctgx+5\cdot x^2+C$