Question

9 1\2:1,9-4 1\5 (6+7 1\2):15
____________+ ________
2,32*15\29+4\5 (1 7\15+1\3)*5

Answer 1

$\frac{9 \frac{1}{2}:1,9-4 \frac{1}{5} }{2,32 * \frac{15}{29}+ \frac{4}{5} } + \frac{(6+7 \frac{1}{2} ) :15}{(1 \frac{7}{15} + \frac{1}{3} )*5} = \frac{ \frac{19}{2}* \frac{10}{19} - 4 \frac{2}{10} }{ \frac{116}{5}* \frac{15}{29} + \frac{8}{10} } + \frac{13 \frac{1}{2} :15}{(1 \frac{7}{15} + \frac{5}{15}) *5 } = \\ \\ = \frac{5 - 4,2}{ \frac{4*3}{1*1} +0,8} + \frac{13,5 : 15 }{1 \frac{4}{5} *5 } = \frac{0,8}{12+0,8} + \frac{0,9}{1,8*5} = \frac{0,8}{12,8} + \frac{0,9}{9} =$
$= \frac{1}{16}+ \frac{1}{10}= 0,0625 + 0,1 = 0,1625$