Question

(0,8)^2x-x^2≥1 помогите пожалуйста

Answer 1

$(0.8)^{2x-x^2}\geq 1 \\\\ (0.8)^{2x-x^2}\geq (0.8)^0 \\\\ 2x-x^2\leq 0 \\\\ x(2-x)\leq0 \\\\ \left \{ {{x \leq 0}} \atop {x \geq 2} \right. \\\\ x\in (-\infty;0] \cup [2;+\infty)$