Question

$\frac{ b^{2} }{36 a^{2}- b^{2} } : \frac{b}{6a-b}$ при a = $\frac{1}{6}$, b = $\frac{1}{9}$

Answer 1

$\frac{ b^{2} }{(6a-b)(6a+b) } * \frac{6a-b}{b} = \frac{b}{6a+b} = \frac{ \frac{1}{9} }{6* \frac{1}{6} + \frac{1}{9} } = \frac{1}{9} * \frac{9}{10} =0.1$