Question

Сравните значения a и b, если
a=0,8^2 - 0,2^ , b= (0,8 - 0,2)^2

Answer 1

$a=0.8^2 - 0.2^ 2\\ \\ a = (0.8 - 0.2)(0.8 + 0.2) = \\ = 0.6 \times 1 = 0.6 \\ \\ b= (0,8 - 0,2)^2 \\ b = {0.8}^{2} - 2 \times 0.8 \times 0.2 + {0.2}^{2} = 0.64 - 0.32 + 0.04 = \\ = 0.36 \\ \\ a = 0.6 \\ b =0 .36 \\ \\ 0.6 > 0.36 \\ a > b$