Question

помогите пожалуйста 49 и 50

Answer 1

49)
$S = \frac{1}{2} * BC * AM = \frac{BC^2*\sqrt{3}}{4} \ |*\frac{4}{BC}\\ 2AM = BC\sqrt{3} \\ 12 \sqrt{3} = BC\sqrt{3} \ | : \sqrt{3} \\ BC = 12 \\ P = 3BC = 36 \ (cm)$

50)
$S = \frac{1}{2} * AC * BK = \frac{AC^2*\sqrt{3}}{4} \ |*\frac{4}{AC}\\ 2BK = AC\sqrt{3} \\ 4 \sqrt{3} = AC\sqrt{3} \ | : \sqrt{3} \\ AC = 4 \\ S = \frac{1}{2} * AC * BK = \frac{1}{2} * 4* 2\sqrt{3} = 4\sqrt{3} \ (cm^2)$