Question

$2\sqrt{6}$ sin8п/3cos25п/4 помогите пожалуйста умоляю

Answer 1

sin(8π/3)=sin(2π + 2π/3)=sin(2π/3)=sin(π/3)=√3/2
cos(25π/4)=cos (6π+π/4)=cos(π/4)=√2/2
$2 \sqrt{6}sin ( \frac{8 \pi }{3})cos ( \frac{25 \pi }{4} )= 2 \sqrt{6}* \frac{ \sqrt{3} }{2} * \frac{ \sqrt{2} }{2} = \frac{ 2\sqrt{6*3*2} }{2*2} = \frac{ \sqrt{6^2} }{2} = \frac{6}{2} =3$