Question

(3,5 - х) (4х+1) + (2х+3) ^2 <0 ,, пж помогите

Answer 1

Во решение на задачу

Answer 2

$\mathtt{(3,5-x)(4x+1)+(2x+3)^2\ \textless \ 0;~2(2x+3)^2-(2x-7)(4x+1)\ \textless \ 0;~}\\\mathtt{2(4x^2+12x+9)-(8x^2-26x-7)\ \textless \ 0;~}\\\mathtt{8x^2+24x+18-8x^2+26x+7\ \textless \ 0;~50x+25\ \textless \ 0;~x\ \textless \ -\frac{25}{50}}$

ОТВЕТ: $\mathtt{x\ \textless \ -\frac{1}{2}}$