Question

Помогите Алгебра 10 класс

Answer 1

$\mathtt{f(x)=x^3-x^2;~f'(x)=3x^2-2x;~f'(x_0)=3+2=5;~}\\\mathtt{f(x)=2+\frac{1}{x};~f'(x)=-x^{-2};~f'(x_0)=-(-1)^{-2}=-1}$


$\mathtt{f(x)=3x^2+3x;~f'(x)=6x+3;~f'(x_0)=6*(-\frac{2}{3})+3=-1;}\\\mathtt{f(x)=1+\frac{3}{x-2};~f'(x)=-\frac{3}{(x-2)^2};~f'(x_0)=-3}$