Question

найдите область определения функции

Answer 1

1)
$y = \frac{x(x - 4)}{x - 4}$
х-4≠0
х≠4
D(y)=(-∞; 4)U(4; +∞)

2)
$y = \frac{x + 6}{5 - x}$
5-x≠0
x≠5
D(y)=(-∞; 5)U(5; +∞)

3)
$y = \frac{x}{12x - 6}$
12x-6≠0
12x≠6
x≠0,5
D(y)=(-∞; 0,5)U(0,5; +∞)

4)
$y = \frac{x + 3}{8 - 4x}$
8-4x≠0
-4x≠-8
x≠2
D(y)=(-∞; 2)U(2; +∞)