Question

Решите:
(x+4)^2=(x-5)^2

Answer 1

$(x+4)^{2} =(x-5)^{2} \\ x^{2} +8x+16= x^{2} -10x+25 \\ x^{2} - x^{2} +8x+10x+16-25=0 \\ 18x-9=0 \\ 18x=9 \\ x=0,5$