Question

Помогите решить .......

Answer 1

1)3^3+4x=1,5*2^3+4x
log(3^3+4x)=log(1,5*2^3+4x)
(3 log (3)+4x log (3))=log(1,5*2^3+4x)
3 log (3)+4x log (3)=log (1,5)+log(2^3+4x)
3 log (3)+4x log (3)=log(1,5*2^3+4x)
3 log (3)+4x log (3)-log(1,5*2^3+4x)=0
x=- 1/2