Question

y=sin^2(2x-3)
Что-то по производным

Answer 1

$y' = (sin^2(2x-3))' = 2sin(2x-3)*(sin(2x-3))' = \\ \\ = 2sin(2x-3)*cos(2x-3) * (2x-3)' = \\ \\ = 2sin(4x-6)$