Question

8*√2*cos(-π/3)*sin(-π/4)-tg(π/4)+ctg(-π/2)

Answer 1

$8 \times \sqrt{2} cos(-\pi/3) \times sin(-\pi/4)-tg(\pi/4)+ctg(-\pi/2) = \\ = 8 \sqrt{2} \times \frac{1}{2} \times ( - \frac{ \sqrt{2} }{2} ) - 1 + 0 = \\ = - \frac{8 \sqrt{2} \sqrt{2} }{4} - 1 = - 4 - 1 = - 5$