Question

уравнение с дробью 2х-7/х+1 +3х+2/х-1=7

Answer 1

$\frac{2x-7}{x+1} + \frac{3x+2}{x-1}=7 \\ (2x-7)(x-1) + (3x+2)(x+1) = 7(x+1)(x-1) \\ 2x^{2} - 9x + 7 + 3x^{2} + 5x + 2 = 7x^{2}-7 \\ 2x^{2} - 7x^{2}- 9x + 7 + 3x^{2} + 5x + 2 + 7 = 0 \\ -2x^{2} - 4x + 16 = 0 \\ 2x^{2} + 4x - 16 = 0 | : 2 \\ x^{2} +2x-8=0 \\ x1 = -4 \\ x2 = 2$

Ответ : -4 и 2