Question

Просто решить систему (легкая)

Answer 1

$\left \{ {2x^2-x=y} \atop {2x-1=y}} \right. \left \{ {x(2x-1)=y} \atop {2x-1=y}} \right. \left \{ {xy=y} (:y) \atop {2x-1=y}} \right. \left \{ {x=1} \atop {2x-1=y}} \right. \left \{ {x=1} \atop {2*1-1=y}} \right. \left \{ {x=1} \atop {1=y}} \right.$

Ответ: (1;1)