Question

ПОМОГИТЕ ПЖ............

Answer 1

$(x+8): \frac{ x^{2} +16x+64}{x-8} = \frac{(x+8)(x-8)}{x^{2} +16x+64} = \frac{(x-8)(x+8)}{(x+8)^{2}} = \frac{x-8}{x+8} = \frac{12-8}{12+8} = \frac{4}{20}=0,2$