Question

ab-4b-2a+8 2a-8-ab+4b
----------------- : -----------------
2a+8-ab-4b ab+4b-2a-8
----это дробь
помогите пж

Answer 1

$\frac{ab-4b-2a+8}{2a+8-ab-4b} : \frac{2a-8-ab+4b}{ab+4b-2a-8} =$
$\frac{a(b-2)-4(b-2)}{a(2-b)+4(2-b)} * \frac{a(b-2)+4(b-2)}{a(2-b)-4(2-b)} =$
$\frac{(b-2)(a-4)(b-2)(a+4)}{(2-b)(a+4)(a-4)(2-b)} =1$