Question

frac {a-5}{5a+25}+frac{3a+5}{a^2+5a}

Answer 1

$frac {a-5}{5a+25}+frac{3a+5}{a^2+5a}=frac {a-5}{5(a+5)}+frac{3a+5}{a(a+5)}=\ =frac {a(a-5)+5(3a+5)}{5a(a+5)}=frac{a^2-5a+15a+25}{5a(a+5)}=\ =frac{a^2+10a+25}{5a(a+5)}=frac{(a+5)^2}{5a(a+5)}=frac{a+5}{5a}$