Question

найдите первые четыре члена арифметической прогрессии если a1=8 d=2

Answer 1

a₂ = a₁ + d = 8 + 2 = 10

a₃ = a₂ + d = 10 + 2 = 12

a₃ = a₂ + d = 12 + 2 = 14

a₄ = a₃ + d = 14 + 2 = 16

Answer 2

${a}^{2} = {a}^{1} + d = 8 + 2 = 10$
${a}^{3} = {a}^{2} + d = 10 + 2 = 12$
${a}^{3} = {a}^{2} + d = 12 + 2 = 14$
${a}^{4} = {a}^{3} + d = 14 + 2 = 16$