Question

20б!!! найти производную функции y=(1-4x)/(x-2)

Answer 1

$y= \frac{1-4x}{x-2}\\\\y'=\frac{-4(x-2)-(1-4x)\cdot 1}{(x-2)^2}= \frac{-4x+8-1+4x}{(x-2)^2}= \frac{7}{(x-2)^2}$