Question

Помогите решить какой- нибудь

Answer 1

$\sqrt{ {80 }^{2} - {48}^{2} } = \\ = \sqrt{(80 - 48)(80 + 48)} = \\ = \sqrt{32 \times 128} = \sqrt{32 \times 32 \times 4} = \\ = 32 \times 2 = 64$
$\sqrt{ {490 }^{2} - {392}^{2} } = \\ = \sqrt{(490 - 392)(490 + 392)} = \\ = \sqrt{98\times 882} = \\ = \sqrt{98 \times 98 \times 9} = 98 \times 3= 294$
$\sqrt{ {178 }^{2} - {160}^{2} } = \\ = \sqrt{(178 - 160)(178 + 160)} = \\ = \sqrt{18\times338} = \\ = \sqrt{9 \times 2 \times 2 \times 169} = \\ = 3 \times 2 \times 13 = 78$
$\sqrt{ {435}^{2} - {72}^{2} } = \\ = \sqrt{(435 - 72)(435+ 72)} = \\ = \sqrt{363\times 507} = \\ = \sqrt{3 \times 121 \times 3 \times 169} = \\ = 3\times 11 \times 13= 429$
$\sqrt{ {771 }^{2} - {96}^{2}} = \\ = \sqrt{(771 - 96)(771 + 96)} = \\ = \sqrt{675 \times 867} = \\ = \sqrt{225 \times 3 \times 3 \times 289} = \\ = 15 \times 3 \times 17 = 765$
$\sqrt{ {195}^{2} - {168}^{2} } = \\ = \sqrt{(195- 168)(195+ 168)} = \\ = \sqrt{27\times 363} = \\ = \sqrt{9 \times 3\times 3 \times 121} = \\ = 3 \times 3\times 11= 99$
$\sqrt{ {520 }^{2} - {200}^{2} } = \\ = \sqrt{(520 - 200)(520 + 200)} = \\ = \sqrt{320\times 720} = \\ = \sqrt{64 \times 5\times 5 \times 144} = \\ = 8\times 5 \times 12= 480$