Question

(2х+1)(х-4)=(х-2)(х+2) помогите

Answer 1

$(2x + 1)(x - 4) = (x - 2)(x +2 ) \\ 2 {x}^{2} - 8x + x - 4 = {x}^{2} - 4 \\ 2 {x}^{2} - 8x + x - 4 - {x}^{2} + 4 = 0 \\ {x}^{2} - 7x = 0 \\ x(x - 7) = 0 \\ x - 7 = 0 \: \: \: \: \: \: \: \: \: \: \: x = 0 \\ x = 7$