Question

sin(α-2π)*cos (3/2π-α)+tg(π-α)*tg(3/2π+α)+cos^2(π\2-α) упростить выражение

Answer 1

Sin(α-2π)*cos (3/2π-α)+tg(π-α)*tg(3/2π+α)+cos^2(π\2-α) =
= Sin(2π-α)*Sinα + tgα *Ctgα + Sin²α = Sinα*Sinα +1 +Sin²α = 2Sin²α