Question

Решите прошу)) Если что это дроби)Заранее спс

Answer 1

197.

$1)\ 7\dfrac9{16}+8\dfrac7{16}=7+8+\dfrac{9+7}{16}=15+\dfrac{16}{16}=15+1\boldsymbol{=16}\\\\\\2)\ 4\dfrac9{19}+5\dfrac{13}{19}=4+5+\dfrac{9+13}{19}=9+\dfrac{22}{19}=9+1\dfrac3{19}\boldsymbol{=10\dfrac3{19}}\\\\\\3)\ 1-\dfrac{16}{25}=\dfrac{25}{25}-\dfrac{16}{25}=\dfrac{25-16}{25}\boldsymbol{=\dfrac9{25}}\\\\\\4)\ 4-1\dfrac7{12}=3\dfrac{12}{12}-1\dfrac7{12}=3-1+\dfrac{12-7}{12}\boldsymbol{=2\dfrac5{12}}$

$5)\ 6\dfrac5{14}-2\dfrac{11}{14}=5\dfrac{19}{14}-2\dfrac{11}{14}=5-2+\dfrac{19-11}{14}=3\dfrac8{14}\boldsymbol{=3\dfrac47}\\\\\\6)\ 19\dfrac{11}{35}-12\dfrac{29}{35}=18\dfrac{46}{35}-12\dfrac{29}{35}=18-12+\dfrac{46-29}{35}\boldsymbol{=6\dfrac{17}{35}}$

198.

$1)\ x+8\dfrac4{29}=12\\\\~~~~~x=12-8\dfrac4{29}\\\\~~~~~x=11\dfrac{29}{29}-8\dfrac4{29}\\\\~~~~~\boxed{\boldsymbol{x=3\dfrac{25}{29}}}\\\\\\2)\ 5\dfrac7{18}-\left(x-2\dfrac5{18}\right)=1\dfrac{11}{18}\\\\~~~~~\left(x-2\dfrac5{18}\right)=5\dfrac7{18}-1\dfrac{11}{18}\\\\~~~~~x-2\dfrac5{18}=4\dfrac{25}{18}-1\dfrac{11}{18}\\\\~~~~~x-2\dfrac5{18}=3\dfrac{14}{18}\\\\~~~~~x=2\dfrac5{18}+3\dfrac{14}{18}\\\\~~~~~x=5\dfrac{19}{18}\\\\~~~~~\boxed{\boldsymbol{x=6\dfrac1{18}}}$