Question

Решите плиз, решение полное

Answer 1

$sin^2(6.4pi) + sin^2(2.9pi)-4tg(1.4pi)*tg(7.1pi)=\ 1-cos^2(6.4pi)+sin^2(2.9pi)=\ sin(0.5pi-(-2.4pi))=cos(2.4pi)\ cos(2.4pi)=cos(6.4pi)\ sin^2(6.4pi) + sin^2(2.9pi)=1\ \ 4tg(1.4pi)tg(7.1pi)=4\ 1-4=-3$